ek physics #9 (displacement graphs) (error?)

[yoyohomieg5432]

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this question seems like there is no correct answer. although they say C is correct. when i look at C i see that displacement doesn't change with time, which to me means 0 velocity?

or if you think of it in a calculus sense, the derivative of displacement is velocity, and since displacement is constant, the derivative of a constant is 0.

anybody have an explanation on how C could be right?

 

[Endure]

this question seems like there is no correct answer. although they say C is correct. when i look at C i see that displacement doesn't change with time, which to me means 0 velocity?

or if you think of it in a calculus sense, the derivative of displacement is velocity, and since displacement is constant, the derivative of a constant is 0.

anybody have an explanation on how C could be right?

(A) is wrong because the slope, v(t), is increasing linearly with time. (B) is wrong because acceleration is constant, indicating that velocity is changing linearly with time (integrating a constant, C, results in Cx – a line with slope C). (D) is absurd since it's depicting an increasing acceleration with time, the derivative of which is referred to as "jerk".

This leaves (C), which is showing a velocity of 0. For the purpose of the question, even though the particle isn't going anywhere, it's velocity is still unchanging. Not sure if this is the correct reasoning, but it's how I'd go about it.