Hello,
This might seem like a dumb question, but I am having problems figuring out how the book derived the following answer to the question below.
#44 "On a particular stretch of wet pavement, the kinetic coefficient of friction u for a particular car with mass m is 0.08. If the car is moving at a velocity v, and suddenly locks its wheels and slides to a stop, which of the following expressions gives the distance that it will slide?"
I know we will be using the following equation: Fk = UkFn
The normal force Fn is equal to the w of the car (mg).
Fk is equal to ma, so the acceleration is ug
If we plug that acceleration into the formula, V^2 = Vo^2 + 2ax the book states that the answer is (v^2 / 2gu).
Can someone please explain how they plugged it in the formula and derived the answer?
Thanks
This might seem like a dumb question, but I am having problems figuring out how the book derived the following answer to the question below.
#44 "On a particular stretch of wet pavement, the kinetic coefficient of friction u for a particular car with mass m is 0.08. If the car is moving at a velocity v, and suddenly locks its wheels and slides to a stop, which of the following expressions gives the distance that it will slide?"
I know we will be using the following equation: Fk = UkFn
The normal force Fn is equal to the w of the car (mg).
Fk is equal to ma, so the acceleration is ug
If we plug that acceleration into the formula, V^2 = Vo^2 + 2ax the book states that the answer is (v^2 / 2gu).
Can someone please explain how they plugged it in the formula and derived the answer?
Thanks