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Hey guys, I'm just a bit stumped right now after doing the practice passage in TBR for the last chapter of general chemistry. I would be so appreciative if someone could lend me a helping hand!
The question that stumped me was passage 13 on page 300, question 83.
This is what is given:
Cu2+ + 2e- --> Cu(s) E= 0.34V
Cu2+ + 1e- --> Cu+ E= 0.15V
Q: What the Gibb's free energy change for the reaction: Cu (s) ---> Cu+ + 1e- ???
Instead of doing their long way of finding the change in Gibb's free energy of the two separate reactions and adding them up, I decided to sum up the E values to find Ecell, and then attempt to find G by using the equation G=-nfE.
Can someone please explain to me why my approach is wrong? :S
My Ecell was calculated to be = -0.34V + 0.15V = -0.19V
Usually Ecell = Ered + Eoxi , without needing to take into account the number of e- . For example, in the 2nd reaction above, we would still use E= 0.15V, instead of 0.30V even though the first reaction has 2e- and the 2nd reaction has 1e-
I'm just really frustrated that I can't figure out what went wrong with my logic..
Someone, please help haha!
Thanks in advance!!!
The question that stumped me was passage 13 on page 300, question 83.
This is what is given:
Cu2+ + 2e- --> Cu(s) E= 0.34V
Cu2+ + 1e- --> Cu+ E= 0.15V
Q: What the Gibb's free energy change for the reaction: Cu (s) ---> Cu+ + 1e- ???
Instead of doing their long way of finding the change in Gibb's free energy of the two separate reactions and adding them up, I decided to sum up the E values to find Ecell, and then attempt to find G by using the equation G=-nfE.
Can someone please explain to me why my approach is wrong? :S
My Ecell was calculated to be = -0.34V + 0.15V = -0.19V
Usually Ecell = Ered + Eoxi , without needing to take into account the number of e- . For example, in the 2nd reaction above, we would still use E= 0.15V, instead of 0.30V even though the first reaction has 2e- and the 2nd reaction has 1e-
I'm just really frustrated that I can't figure out what went wrong with my logic..
Someone, please help haha!
Thanks in advance!!!