Equation of the line

[anteater85]

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what's the equation of the line passing through the points (-6, -1) and (2,14).

I got the slope to be 15/8 but I forgot how to get the y-intercept. can someone help me plz.

 

[marcusho]

plug the points into " y=mx + b " where b is the y intercept.

14 = (15/8)(2) + b
b = 10.25

-1 = (15/8)(-6) + b
b = 10.25

formula would be y = (15/8)x + 10.25

 

[bennijai]

You find the slope (m) by using the slop formula: [y1-y2]/[x1-x2] = 15/8

For the intercept you need to basically plug in the values into the equation: y= mx + b. The 'b' is the intercept.

Using one of the points, (-6, -1)
y = mx + b
-1 = (15/8)(-6) + b
-1 = -90/8 + b
b = 81/8

Put everything together y = 90/8x + 81/8

EDIT: marcusho beat me to it. lol.

 

[anteater85]

You find the slope (m) by using the slop formula: [y1-y2]/[x1-x2] = 15/8

For the intercept you need to basically plug in the values into the equation: y= mx + b. The 'b' is the intercept.

Using one of the points, (-6, -1)
y = mx + b
-1 = (15/8)(-6) + b
-1 = -90/8 + b
b = 81/8

Put everything together y = 90/8x + 81/8

EDIT: marcusho beat me to it. lol.

thx to both of u guys 🙂

 

[Streetwolf]

what's the equation of the line passing through the points (-6, -1) and (2,14).

I got the slope to be 15/8 but I forgot how to get the y-intercept. can someone help me plz.

Alternatively use point-slope and you won't need to get the y-intercept. You just need one point and the slope!

(y-y1) = m(x-x1)

(y-14) = 15/8(x-2)

y-14 = (15/8)x - 15/4
y = (15/8)x +41/4

 

[EyEnStein 07]

point slope formula that StreetWolf posted is the way to go👍

 

[marscole]

(y1-y2)/(x1-x2) = (y-y1)/(x-x1)

you will equation with 2 points...