Kneecoal Full Member 10+ Year Member May 24, 2009 #1 Advertisement - Members don't see this ad in a kaplan example, they give a Ka problem where the gist is this: Ka = [x][x] = 1.8 x 10^-5 [2.0] and they get x to = 6.0 x 10^-3 so if you get x^2 = 3.6 x 10^-5, what's an easy way to find the square root of this to get x?
Advertisement - Members don't see this ad in a kaplan example, they give a Ka problem where the gist is this: Ka = [x][x] = 1.8 x 10^-5 [2.0] and they get x to = 6.0 x 10^-3 so if you get x^2 = 3.6 x 10^-5, what's an easy way to find the square root of this to get x?
J jbrenn4 Full Member 10+ Year Member May 24, 2009 #2 I would work with the scientific notation given......3.6 E -5 can be written as 36 E-6.....thus the square root would be easy....6 E-3 Upvote 0 Downvote
I would work with the scientific notation given......3.6 E -5 can be written as 36 E-6.....thus the square root would be easy....6 E-3
