Fundamental wavelength of an open pipe (AAMC4)

[sc4s2cg]

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How does one figure out the wavelength of a pipe with both ends open? I cannot find the equation anywhere...

This is AAMC 4, PS 34

 

[pm1]

How does one figure out the wavelength of a pipe with both ends open? I cannot find the equation anywhere...

This is AAMC 3, PS 34

wavelength = 2L / n (the way I remember.. Tulane)

(L is the length of the pipe, and n is 1 for first harmonic, 2 for second and etc)

For pipes closed at one end and open at the other

wavelength = 4L / n (but here n can only be odd numbers)

 

[nabilesmail]

For pipes, remember that an open end is ALWAYS an antinode, and a closed end is ALWAYS a node (for fundamental)

if both sides are antinodes, the distance between them has to be 1/2 the wavelength. Therefore the wavelength is 2 times this distance, or 2 times the length of the pipe.

For a closed one end and open one end pipe.

The closed side = node, open side = antinode, therefore the distance between them is 1/4 lambda.
Therefore the wavelength will be 4L

=]