Gchem Achiever Question

[suhshi]

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determine the value of x if 10 grams of CuSO4 xh20 have been dehydrated to 6.4g of anhydrous CuSO4

Im not really understanding their explanation.
Can anybody explain this?

Answer is x= 5

 

[UCB05]

determine the value of x if 10 grams of CuSO4 xh20 have been dehydrated to 6.4g of anhydrous CuSO4

Im not really understanding their explanation.
Can anybody explain this?

Answer is x= 5

CuSO4 = 161.4g/mol
H2O = 18g/mol

10g CuSO4 xH2O dehydrates to 6.4g CuSO4
That means 6.4g CuSO4 + 3.6g H2O in the hydrated molecule

6.4g CuSO4 = 0.039mol CuSO4 ~~0.04mol CuSO4
3.6g H2O = .2mol H2O

10g of the original sample had 0.04mol CuSO4 and .2mol H2O, giving you a ratio of 1:5. The original sample had the formula CuSO4 . 5H2O, x=5

 

[kkmaths90]

Good one...and Good explanation too Thank you 👍

 

[suhshi]

thanks UCB