gen chem question.

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savvysearch

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please help. Thanks.

when 14.250 moles of PCl5 gas is placed in 3 L container and comes to equilibrum at constant temp. 40% of PCl5 decomposes according to:

PCl5 --><-- PCl3 +Cl2

what is Kc value?

Answer: (1.862)(1.862)/2.854

why?


what is the net ionic equation?
HCl+NaOH -->H20 + NaCl

answer:
H30+(aq)+0H-(aq)-->2H20 (l)

why?
 
Make and ICE table to solve this, then it will be clear

PCl5 --><-- PCl3 +Cl2
Initial: 4.75M 0M 0M
Change: -x x x
Equilbri: 4.75-x x x
2.854 1.896 1.896

Since the problem says that 40% of PCl5 is used up, then 60% is remaining at equilibrium so that is where you get 2.854M. 14.25mol/3L x 60%= 2.854M
Knowing this one equilibrium factor, you make the ICE table and solve for the X variable, which in this case is conveniently what the two products are.

Do some more equilibrium problems, the more you do, the easier it'll get.

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For that net ionic one, I think its just H20 because you exclude anything insoluble like salt(NaCl) which would form a solid. I'm not sure though, double check.
 
Na and Cl form precipitate .

Hydronium ion and OH remain soluble . The net ionic eqn discounts whatever precipitates out.

TF
 
thanks! can someone answer the second one?
 
Well, depends if the solution is saturated or not.


NaCl can precipitate out of a super-saturated sol'n


But this has no relevance to the original problem posted.
 
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