General Chemistry Questions

[okklee]

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1) A solution of LiCl has a density of 1.13 g/cm^3 at 25 Celcius. If the solution is 20% by weight LiCl, which is the molarity?

a) 7.6M
b) 0.25M
c) 5.3M
d) 11.2M
e) 1.5M
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2) For silicon, which ionization energy would you predict to be exceptionally large as compared to the preceding ionization energy value?

a) 1st
b) 2nd
c) 3rd
d) 4th
e) 5th
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3) Which of these have the greates ionization energy?

a) Na+
b) Ne
c) Na
d) Mg
e) Kr
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4) When one atom donates both electrons, what type of bond is formed?

a) Ionic
b) Network covalent
c) Coordinate covalent
d) Hydrogen bond
e) Dispersion attraction
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5) Which specie has the most unpaired electrons?

a)Na
b) I
c) Fe
d) Cu
e) Cr

 

[299678]

1. (20g LICl /100 g of solution) x (1 mole of licl/42g) x (1.13g/cm^3) x (1cm^3/0.001L) = 5.3 M

2. Silicon has maximum oxidation number -4 to +4, so 5th ionization energy will be large since it should break the octet

3.Na+
Cation has a smaller radius so stronger attraction with nucleus so greater ionization energy
4) Polar Coordinate covalent bond since it donate both electrons

5) Which specie has the most unpaired electrons?
Cr 4S^1 3d^5 has maximum 6 unpaired electrons

correct me if I am wrong

 

[299678]

Any solution? I need to know if my answer is right or wrong since nobody pm on this

 

[UndergradGuy7]

1. (20g LICl /100 g of solution) x (1 mole of licl/42g) x (1.13g/cm^3) x (1cm^3/0.001L) = 5.3 M

2. Silicon has maximum oxidation number -4 to +4, so 5th ionization energy will be large since it should break the octet

3.Na+
Cation has a smaller radius so stronger attraction with nucleus so greater ionization energy
4) Polar Coordinate covalent bond since it donate both electrons

5) Which specie has the most unpaired electrons?
Cr 4S^1 3d^5 has maximum 6 unpaired electrons

correct me if I am wrong

I just started studying a little.
I agree, with #1, 2, I also think 3 and 5 are right.
4 I don't know, but googled it and I think you the coordinate covalent bond is right.

 

[299678]

Thank you. I am very positive for #4