half-rxn calculation

[Smooth Operater]

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Q: the number of coulombs needed to form a mole of Ag, from a 2L 0.5 M solution of AgNO3, as per the half-rxn given below, would be (1 Coulomb = 6e19 electrons)

Ag + e ---> Ag



c. 6.03e23/6e19

d. 6.03e23/6e19 * 2 * 0.5

I chose C. , but the right answer is D. I think both choices yield the same answer. Am I right?

 

[714guy]

Q: the number of coulombs needed to form a mole of Ag, from a 2L 0.5 M solution of AgNO3, as per the half-rxn given below, would be (1 Coulomb = 6e19 electrons)

Ag + e ---> Ag



c. 6.03e23/6e19

d. 6.03e23/6e19 * 2 * 0.5

I chose C. , but the right answer is D. I think both choices yield the same answer. Am I right?

yes both will yield the same amount since .5 *2 = 1. I think they maybe want you to show how you got the 1 mole of Ag.