Hard Specific Gravity Queston

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Smooth Operater

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An aqueous sulfuric acid solution is 39.2% H2SO4 by
mass and has a specific gravity of 1.25. How many
milliliters of this solution are required to make 100 mL
of a 0.20 M sulfuric acid solution? (FW of H2SO4 = 98
g/mol)

A. 1.6
B. 3.0
C. 4.0
D. 5.0
E. 6.25

the correct answer is 4. But can anyone show a step by step calculation to reach the answer with explanations. Kaplan has its own solution, but I think there may be other ways to think about this Q. Thanks!
 
Here's how I did it:

(1.25 g/mL)(39.2g/100g)(1mol/98g)(1000mL/1L) = 5M

M1V1=M2V2
(5M)V1=(0.2M)(100mL)
V1=4

Dimensional analysis always works great. I'm not sure how Kaplan did it, but this way works.

aranjuez
 
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