-
CycleTrack and SDN are teaming up to make medical school admissions more transparent and accessible! Read the announcement to learn how we’re supporting the future of CycleTrack’s free application-tracking tools .
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
HCL + CO3 (2-) ---> CO2. Why?
Started by Dharma
Get help with your application
Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.
so this one probably has a very simple explanation but i'm a bit pooped out, so maybe you can help me.
Why is carbon dioxide a product of this reaction and what are the other products besides CO2?
H20 should be a product as well
if we balance the equation we should find two H+ floating around, and thus we'll end up getting H2CO3 (carbonic acid) which dissociates to CO2 and H20
H20 should be a product as well
if we balance the equation we should find two H+ floating around, and thus we'll end up getting H2CO3 (carbonic acid) which dissociates to CO2 and H20
I thought that the carbonic acid would form. How does it dissociate into CO2? I'm assuming 2 protons "attack" one of those O with an extra e-, resulting in water. yes? no?
I thought that the carbonic acid would form. How does it dissociate into CO2? I'm assuming 2 protons "attack" one of those O with an extra e-, resulting in water. yes? no?
carbonic acid does form, but we show the reaction going to completion resulting in its dissociation into CO2 and H20
2 HCl + CO3(-2) --> H2CO3 <--> CO2(g) + H20(l) + 2Cl-
carbonate is a moderately strong base so it's going to abstract the protons from HCl and form H2CO3 (that's about all you need to know for the mechanism) which is in equilibrium with H20 and CO2.
we can also write it as:
2 HCl + CO3(-2) --> CO2(g) + H20(l) + 2Cl-
does that help?
Advertisement - Members don't see this ad
Carbonic acid is just unstable. It automatically degrades into H2O and CO2, which are just the lewis acid (CO2) and attacking base (H2O) forms of carbonic acid.
That's certainly one reason you could expect this reaction to proceed to completion for the most part. In general there is an equilibrium established between H2CO3, HCO3 and H+ , and CO2 + H2O. This equilibrium is important for the maintenance of blood pH as well and understanding the relationship between pulmonary ventilation and blood pH. The reaction hasn't proceeded to completion at the step you isolated (H2CO3 -> H+ and HCO3+) although this step does exist and forms part of the equilibrium equation.
Hope this helps somewhat.
Hope this helps somewhat.
carbonic acid does form, but we show the reaction going to completion resulting in its dissociation into CO2 and H20
2 HCl + CO3(-2) --> H2CO3 <--> CO2(g) + H20(l) + 2Cl-
carbonate is a moderately strong base so it's going to abstract the protons from HCl and form H2CO3 (that's about all you need to know for the mechanism) which is in equilibrium with H20 and CO2.
we can also write it as:
2 HCl + CO3(-2) --> CO2(g) + H20(l) + 2Cl-
does that help?
Nucleophile attacks electrophile. Oxygen attacks hydrogen and forms bicarb ion. This can continue until "carbonic acid" is formed.