help with calculation please

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xoangelxo

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how would you go about doing this calculation: ((10^-5)^2) / .02 ????
 
how would you go about doing this calculation: ((10^-5)^2) / .02 ????

Well:

((10^-5)^2) = 10^-10

so, now you have 10^-10/.02 , now you can move the 2 decimal places to the right of the denominator and times the numerator by 100 (since you move 2 decimal places in the denominator) to get: 10^-8/2, which is equal to:
1 x 10^-8/2
0.5 x 10^-8 = 5 x 10^-9

*plz correct me if I am wrong!
 
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