Help With Chemistry Problem

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how do you solve this question ..How many milliliters of 3.0 M H2SO4 are required to neutralize 30.0 ml of 4.0 M NaOH?

M1V1 = M2V2
V1 = 4 x 30 / (3 x 2) = 20 ml

Note that M1 is 3.0 x 2 because every mole of H2SO4 gives 2 mole of [H+].

I hope you can catch it here.
 
thanks alot ..I have been so confused about it..I used the neutralization equation but i couldnt get the answer because I dont really understand the concept of Normality.
 
how do you solve this question ..How many milliliters of 3.0 M H2SO4 are required to neutralize 30.0 ml of 4.0 M NaOH?

That's right!
Whenever you have problem where #H+ not equal to #OH-(H2SO4 and NaOH), you use N1V1=N2V2.

OH in this case is still M=1x4.0M=N1
H2 then is M=2X3.0M=N2

Correct me if I am wrong...
 
just remember this:

1)for dilution problems: M1V1=M2V2

2)for nutralization and titration: N1V1=N2V2

that is the only way to do these kind of problems !!!
 
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