I tend to write out the number of each atom appearing on each side to keep track of my math. From there, speed is all about practice.
Would look like this:
_C6H12O2 + _O2 --> _CO2 + _H20
6C............................1C
12H..........................3O
4O............................2H
*Balance the atoms appearing in only one species first [Here: Carbon first, so 1C6H12O2 and 6CO2]
*Rebalance the numbers under each reaction side [6C, 12 H, 4O --> 6C, 13O, 2H]
*Repeat step one [Hydrogen second, so, again, 1C6H12O2 and 6H2O]
*Rebalance again [6C, 12 H, 4O --> 6C, 18O, 12H]
*Continue with atoms appearing in more than one species [Oxygen last]
Dunno if that helps, but it works out better than random number plugging for me. Pretty quick after a few practice tries too.