How does Diazonium salt work?

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sfoksn

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Hello, if we have p-nitro bromobenzene and we treat it with Cl2/H2O, we get a diazonium salt.

How exactly does this happen?

I thought it would not be favorable to break the aromaticity of the benzene so the Cl would not be able to kick off the H and replace itself.


Can anyone provide me why?


Thank you.
 
^I'll look this up for you. I'm going through my old OChem notes. I know we discussed it somewhere. When I find it, I'll scan/transcribe it onto here. that is if no one else answers...I'm also curious as well
 
Thanks.. if you look at my other questions, no one answers my question very clearly..

its weird 🙁
 
are you sure about the reagents (Cl2/H2O)?

because nitrobenzene should be treated with Zn/HCl or SnCl2/HCl to make the diazonium salt...but I guess you could infer (if these are your actual reagents) that the nitrobenzene has been reduced to an aminobenzene (with H from H2O donated to this structure to form the diazonium salt). At least that's what I'm seeing from my notes that I took a few years ago...
 
Hm.. yeah.. I think when I posted I was too sleepy.. Here is the picture:


So the benzene with Br and NH2 gets treated with Cl2/H2O and Cl2 is able to replace the H's on benzene, and I am very confused about that.

Also, when the third benzene (Br, NH2, Cl, Cl) gets treated with NaNO2, HCl at 5 celcius, it gets turned into salt... Could you tell me why?

Then H3PO2 is able to kick off the N2+ Cl- salt group from the benzene..

I do not understand any of the mechanisms and why it happens..

Sorry about the error, AmpedUp!
 
I think that's because NH2 is a o/p director (and activating) in electrophilic substitution. At these two positions, the unshared electrons on NH2 can stabilize the carbocation but at the meta position they can't.

Br is also o/p directing, but it is deactivating and I've learned that you always go with the activator.
 
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