How to get slope from an equation?

[cbs21]

For example, say the graph is frequency 👍 by n (x)

from the equation f = nv/2L

If you do f/n = v/2L is v/2L equal to the slope? Or do you have to do n/f as in y/x? I don't know if my example is clear. But just in general how do you relate the x and y axis to make it equal to the slope?

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[novawildcat]

For example, say the graph is frequency (x) by n 👍

from the equation f = nv/2L

If you do f/n = v/2L is v/2L equal to the slope? Or do you have to do n/f as in y/x? I don't know if my example is clear. But just in general how do you relate the x and y axis to make it equal to the slope?

Just identify what are the independent and dependent variables. Anything that is in front of the independent variable will be your slope. Anything that is added or subtracted from the independent variable will be your intercept.

 

[cbs21]

so i forgot what independent and dependent variables were but wiki says x is the indep. and y is dependent. so

So since n is the independent then v/2L is the slope because it is multiplied by n. OKAY thanks! But can I always assume that indpendent is x and dependent is y?

 

[novawildcat]

so i forgot what independent and dependent variables were but wiki says x is the indep. and y is dependent. so

So since n is the independent then v/2L is the slope because it is multiplied by n. OKAY thanks! But can I always assume that indpendent is x and dependent is y?

Yeah you got it. Just remember that in a lab, x, aka the independent variable is always the thing that you change. Y, aka the dependent variable is always the thing that you observe changes in in response to a change in 'x'.

 

[mooshika]

For me the easiest thing to do is just put the information into the "y=mx+b" format, m=slope.

So for your problem f="y" n="x" f=(m)n+b, so f=(v/2L)n + 0

Your slope is (v/2L)