how would you know that Xe has 6 pairs of electrons?

[elz787]

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and all the info you are given is that it is in a compound of XeF4

 

[Flipper405]

and all the info you are given is that it is in a compound of XeF4

I would think it would have 4 pairs? 😕

 

[mochafreak]

I remember that one...the way I did it was, first I thought wtf because Xe is a noble gas and it doesn't want to react with crap. But, when you put the 4 flourines around it, you know that they are single bonds because F's bond with single bond only. Xe must have 2 lone pairs in addition to the four e- to get the 8 e- that it usually has.

 

[elz787]

Thanksssssssss

 

[joonkimdds]

Thanksssssssss

Instaed of how does it have 6 pairs, ask how do u draw XeF4?
then it could be a lot easier...-_-;
first...Xe = 8 valance electron, F = 7 valance x 4 = 28
total = 36

u draw Xe in the middle and F around.
Each of them has single bond = 4 singlebond X2 = 8 valance electron.
36 - 8 = 28 left
6 valance electrons around each F with dots.
6 x 4 = 24
so 28 left - 24 = 4.
2, 2 pair. = makes them 2 pairs.

any more question?

 

[elz787]

i don't want to spend my time on the dat drawing dots.

 

[joonkimdds]

i don't want to spend my time on the dat drawing dots.

it takes less than 20 sec for me to finish drawing that...

 

[Richnator]

you dont have to draw dots, you can do it in your head. I just did it looking at the periodic tables and caculating each bond is 2 electrions times 4, since 4 flourines. That is 36-8, then subtract 24(6x4) to get 4. 4 divided by 2= 2 lone pairs

 

[joonkimdds]

you dont have to draw dots, you can do it in your head. I just did it looking at the periodic tables and caculating each bond is 2 electrions times 4, since 4 flourines. That is 36-8, then subtract 24(6x4) to get 4. 4 divided by 2= 2 lone pairs

yeah, we can do it in our head 😀