How would you solve this QR?

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wouldnt x just be = to 19?

This is what I got. The solution RSD did you need to do the quadratic and I didn't get the same answer as him. What you can do instead is factor.

Like so
sqrt(x^2-9) / sqrt(x+3) = 4
or
(x^2-9)^(1/2) / (x+3)^(1/2) = 4
If you factor the top you get [(x-3)^(0.5) * (x+3)^(0.5) ]/ (x+3)^(0.5) = 4
The (x+3)^(0.5) cancel. You get (x-3)^0.5 = 4
Square both sides
x-3 = 16
x=19
 
y = (x+4)/(x+6). What is x =

Multiply by (x+6) on each side.
👍*(x+6) = (x+4)
distribute left side yx +6y = (x+4)
Make all parts of the equation with x on one side and everything else on the other side.
6y -4 = x -yx
Factor the right side
6y - 4 = (1-y) * x
Now this goes to (6y-4)/(1-y) = x


Did you still need this one solved Represent y = (x+5)/(x-9) in form of x= ?
It is the same as the one above I think.
 
Wow, thank you so much.

I didn't know it could be done so simply.

How are you doing in QR section? you must be doing well
 
I haven't started that yet. I touched up on some Gen Chem and doing Bio now. I am pretty good at Algebra, but kinda rusty on trig.
 
End of May hopefully, if I finish studying everything. But it is annoying studying during classes. Can only study DAT stuff 2 days a week or so.
 
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