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I know that the Intensity of Sound can be written as Power/Area; or Energy/Volume x (velocity); Would it then be right to think of Intensity this way, a wave carries energy that is propagating in space (volume) and it travels with a certain velocity?
Also, another thing not mentioned in other posts that I searched is that Intensity follows the INVERSE SQUARE LAW; I= 1/(d)^2
So, does this mean that for the distance in the equation, that the farther and farther the wave travels, the more of the sound begins to die off; Or does this increase mean that the farther and farther the sound is, the less the intensity is PERCEIVED by the human ear? (i know the other equation which also has to do with this B=10 log I/I0) but I was specifically wondering in the context of the inverse square law.
Also, another thing not mentioned in other posts that I searched is that Intensity follows the INVERSE SQUARE LAW; I= 1/(d)^2
So, does this mean that for the distance in the equation, that the farther and farther the wave travels, the more of the sound begins to die off; Or does this increase mean that the farther and farther the sound is, the less the intensity is PERCEIVED by the human ear? (i know the other equation which also has to do with this B=10 log I/I0) but I was specifically wondering in the context of the inverse square law.
