I think I know the answer to this, example 9.1b (pg. 174 of the 2012 copy) in the TBR book explains this concept pretty well. The internal resistance decreases power drain to the circuit. The more the internal resistance reduced the amount of current, the more it decreases the power drain. This is your answer OP
I would like to hear a second opinion about this, since I believe since P=I^2R, this would show that increasing the resistance will lead to far less current. Since current is squared in the equation, the power drain would be reduced greatly. Or should I assume that since, "V= electromotive force - Ir" that if the internal resistance increases that this decreases the V. Since P=IV, this would mean that P would decrease as a result of decreasing V.