I am confused about the exemption to the general IE trend in the case of Nitrogen to Oxygen.
According to Khan video, if we draw out the electron configuration, there is repulsion between the paired electrons in the 2p orbital in oxygen, making it easier to remove the electron so the IE is lower than that of nitrogen.
Using the same principle, if we look at the example of S and Cl and drawing out the electron configuration, wouldn't Cl have a lower IE than S? I know the general trend in IE but applying the same logic as explained in the Khan video to this example doesn't work.
According to Khan video, if we draw out the electron configuration, there is repulsion between the paired electrons in the 2p orbital in oxygen, making it easier to remove the electron so the IE is lower than that of nitrogen.
Using the same principle, if we look at the example of S and Cl and drawing out the electron configuration, wouldn't Cl have a lower IE than S? I know the general trend in IE but applying the same logic as explained in the Khan video to this example doesn't work.