Is this the correct mechanism for saponification?

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510586

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These are the notes I took from Chad. How come the oh is on glyxerol? The mechanism makes it look like the OH goes with the fatty acid. Maybe I wrote it down wrong

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It's because once the glycerol chain leaves, the O's want to abstract the H's from the OH that attacked the carbonyl in order to become more stable. The negative charge on the O can be better resonated with the double bonded O than if the negative charges remained on the glycerol O's. Basically, the alkoxide (glycerol without the H's) functions as a stronger base than the carboxylic acid's conjugate base, so a rapid acid-base reaction occurs.
 
It's because once the glycerol chain leaves, the O's want to abstract the H's from the OH that attacked the carbonyl in order to become more stable. The negative charge on the O can be better resonated with the double bonded O than if the negative charges remained on the glycerol O's. Basically, the alkoxide (glycerol without the H's) functions as a stronger base than the carboxylic acid's conjugate base, so a rapid acid-base reaction occurs.
Awesome than you!
 
Think this as a reaction where an ester is hydrolyzed in the presence of a base (i.e. NaOH). The end products should be an alcohol and carboxylic acid.
 
Think this as a reaction where an ester is hydrolyzed in the presence of a base (i.e. NaOH). The end products should be an alcohol and carboxylic acid.
Oh yea i was unsure why it was an alcohol on glycerol instead of the other side but I understand it now. THanks
 
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