When the starting conditions of a reaction are out of balance with Keq, Le Chet explains how products and reactants will adjust to reflect the Keq value. How would this work in a scenario where you have A+B <-> C+D when one product/reactant is too high and the other is too low?
For ex, if Keq=4 and you have 12 moles of gas, ideally at equilibrium you'd have [C]=[D]=4 and [A]=2 giving (4x4)/(2x2)=16/4=4.
What if instead you start with [C]=8 and [D]=2, would they both move towards an equal value? Same thing for an uneven distribution of reactants?
Hope this is clear...?
For ex, if Keq=4 and you have 12 moles of gas, ideally at equilibrium you'd have [C]=[D]=4 and [A]=2 giving (4x4)/(2x2)=16/4=4.
What if instead you start with [C]=8 and [D]=2, would they both move towards an equal value? Same thing for an uneven distribution of reactants?
Hope this is clear...?