kinetic energy of the projectile at the top of the arc?

[adrakdavra]

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A projectile is shot at an angle of θ with an initial speed of v0. What is the kinetic energy of the projectile at the top of the arc?

Ans : 1/2MV2 COS2 theta ????

 

[milski]

At the top the vertical component of velocity is 0 and the total velocity is parallel to the ground and equal to V_x. V_x=Vcosθ, just plug this in K=1/2 mv²

 

[adrakdavra]

At the top the vertical component of velocity is 0 and the total velocity is parallel to the ground and equal to V_x. V_x=Vcosθ, just plug this in K=1/2 mv²

shouldn't the kinetic energy of the projectile at the top of the arc be zero

 

[milski]

shouldn't the kinetic energy of the projectile at the top of the arc be zero

The only way for KE to be zero if the projectile is not moving. That would be the case when the projectile was shot straight up. If it was shot at an angle, there will be a horizontal component which never changes through the flight of the projectile.

 

[adrakdavra]

The only way for KE to be zero if the projectile is not moving. That would be the case when the projectile was shot straight up. If it was shot at an angle, there will be a horizontal component which never changes through the flight of the projectile.

I see , thanks a lot man.