Light Question

[TheRealAngeleno]

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When a beam composed of red and blue light is incident on a glass surface:

A. The blue light is refracted more
B. The red light is refracted more
C. Both colors are refracted equally
D. Neither color is refracted

So I know that blue light has the higher index of refraction, so when refracted it would bend away from the normal more than red light. Does this mean that it is refracted less since it bends away from the normal compared than red light? Thanks guys.

 

[costales]

It's a direct result of Snell's law: n1sin(theta1) = n2sin(theta2), n1 = 1 for air, n2 is value for glass. n2 blue > n2 red, so for the same angle of incidence theta1, the angle of refraction theta2 blue < theta2 red. Therefore blue is refracted more because the smaller theta2 means it is further away from the direction of the original incident ray (remember theta1 and theta2 are measured from the normal).