Math destroyer Q

[Troyvdg]

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x^2 - 2x < 0 which of the following intervals represents the solution set for x?

A. (2, &#8734;)
B. (-&#8734;,2)
C. (0,2)
D. (-&#8734;, 0) union (2, &#8734;)
E. (-&#8734;,0)


how do I solve this?

 

[Msmouth]

x^2 - 2x < 0 which of the following intervals represents the solution set for x?

A. (2, &#8734;)
B. (-&#8734;,2)
C. (0,2)
D. (-&#8734;, 0) union (2, &#8734;)
E. (-&#8734;,0)


how do I solve this?

x(x-2)

the zeros are 0,2

Is C the answer?

 

[BRZ24]

x^2 - 2x < 0 which of the following intervals represents the solution set for x?

A. (2, &#8734;)
B. (-&#8734;,2)
C. (0,2)
D. (-&#8734;, 0) union (2, &#8734;)
E. (-&#8734;,0)


how do I solve this?

Although i just took my DAT yesterday and still feel like ****. I'll try to help lmao

x^2-2x<0

factor
x(x-2)=0

x=0 x=2
now you have two solution so you must create a number line and check

pick a number less than 0 and then 0 and then a number between 0 and 2 and then 2 and then a number bigger than 2. Check and see if it satisfies the original inequality. You will find out at the end that only numbers between 0 and 2 will satisfy the inequality but 0 and 2 will NOT be included (0,2)