math destroyer test 15 Q 10, 11

[Dwight Beet Farm]

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I am rusty on math. Here is question 10: if -2≤x ≤ 4 and -3 ≤ y ≤ 2, what is the smallest possible value of x-y?
question 11: if -2≤x ≤y and -3 ≤y ≤ 2, what is the smallest possible value of (x-y)^2?

 

[DAT Destroyer]

I am rusty on math. Here is question 10: if -2≤x ≤ 4 and -3 ≤ y ≤ 2, what is the smallest possible value of x-y?
question 11: if -2≤x ≤y and -3 ≤y ≤ 2, what is the smallest possible value of (x-y)^2?

For q10 you need to find the range of x - y.
To find the smallest possible value you subtract the largest value of y from the smallest possible value of x and you get : -2-2=-4. To find the largest possible value of x- y , you subtract the smallest value of y from the largest value of x and you get : 4+3=7.
The range of (x-y) is between -4 and 7
therefore that's the smallest possible value.

For q 11 when you square (x-y) you get positive values and the smallest is 0

 

[Dwight Beet Farm]

Makes sense now. Thank you

 

[dentist_dude]

To find the smallest possible value you subtract the largest value of y from the smallest possible value of x and you get : -2-2=-4.

wouldn't this be the smallest value of y-x instead of x-y which what they asked for

 

[DAT Destroyer]

wouldn't this be the smallest value of y-x instead of x-y which what they asked for

For (x - y) to be as small as possible, x has to have the smallest value and y the largest value, hence -2-2=-4
For (y - x ) it would be: -3-4= -7
subtracting y from x means: x - y not y - x

Hope this helps!

 

[dentist_dude]

subtracting y from x means: x - y not y - x

Thank you