So the question states:
"Two normal dice are rolled. What is the probability of getting a sum less than ten?"
Well I understand that it will be easier to use complementary method and the possibility of having sum of 10 or 11 or 12 are as follwos:
For 10: 5+5, 4+6, 6+4
For 11: 5+6, 6+5
For 12: 6+6
Hence, the probability is (3/36)+(2/36)+(1/36) from using product and addition rule of probability which comes out to be 6/36 = 1/6 hence 1-1/6 = 5/6
My question is that why can't we have 2 times 5+5 and 6+6 because either of dice can both through 5 or 6 alternatively so the probability would be: (4/36)+(2/36)+(2/36) = 8/36 = 2/9 ??
Any help would help, thanks!!
"Two normal dice are rolled. What is the probability of getting a sum less than ten?"
Well I understand that it will be easier to use complementary method and the possibility of having sum of 10 or 11 or 12 are as follwos:
For 10: 5+5, 4+6, 6+4
For 11: 5+6, 6+5
For 12: 6+6
Hence, the probability is (3/36)+(2/36)+(1/36) from using product and addition rule of probability which comes out to be 6/36 = 1/6 hence 1-1/6 = 5/6
My question is that why can't we have 2 times 5+5 and 6+6 because either of dice can both through 5 or 6 alternatively so the probability would be: (4/36)+(2/36)+(2/36) = 8/36 = 2/9 ??
Any help would help, thanks!!
