Math question help please

[DDSelin2mori]

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With one fair die what is the probability of having two fours in five attempt?

I'm solving in this way 5C2/6^5 which is wrong!! why this is wrong? and how do you solve it?
thanks

 

[Streetwolf]

(5C2) chooses the rolls which are 4s.
(1/6)^2 describes the rolls which are 4s.
(5/6)^3 describes the other rolls which are not 4s.

So you have (5C2)*(1/6)^2*(5/6)^3.

Your answer needs to be multiplied by 5^3 = 125.