Here’s a fun one from Dr. Romano’s Math Destroyer!
Solution:
0.11(10,000) + 0.07(X) = 2,000
1,100 + 0.07X = 2,000
0.07X = 900 → X = 12,857
% Difference = (12,857 − 10,000) / 10,000 × 100 = 28.57%
✅ Answer: B (28.57%)
Great practice for proportional reasoning — a topic that shows up often on the DAT Quantitative Reasoning section.
Mr. Sharp bought two used cars, fixed them, and sold them both for a profit.
What was the % difference between the money spent on the first versus the second car?
- First car cost: $10,000, sold at 11% profit
- Second car sold at 7% profit
- Total profit = $2,000
A) 30%
B) 28.57%
C) 82.57%
D) 32.57%
E) 23.57%
Solution:
0.11(10,000) + 0.07(X) = 2,000
1,100 + 0.07X = 2,000
0.07X = 900 → X = 12,857
% Difference = (12,857 − 10,000) / 10,000 × 100 = 28.57%
✅ Answer: B (28.57%)
Great practice for proportional reasoning — a topic that shows up often on the DAT Quantitative Reasoning section.