naplex

[kt44]

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plz help me in solving this calculation problem. how much drug should be added to 30ml of water to make a 10% w/w solution.
correct answer is 3.33/
thanks in advance.

 

[kt44]

30 mls of water = 30 g of water

Drug X 10 g
________ = _____
Drug X + 30 g 100 g


100 x = 10 x + 300

90 x = 300

x = 3.33 g

thanks but can u explain all steps

 

[kt44]

So we know that the specific gravity of water is 1g/1ml so that means 30 mls of water equals 30 g.

And what we know about the 10% w/w solution is 10 g of drug / 100 g of total solution

So drug X is being added to the 30 g of water which means the total solution will equal 30 + x.

Now I like to set up ratios becuse it's easy to do and i can see everything.

Drug X / (Drug X + 30) should equal 10 g of drug / 100 of total solution ( since the this addition should equal 10% w/w)

Then solve for x

thank you so much

 

[kt44]

plz help me in solving these calculations.
1- how many grams of boric acid should be used in compounding the following prescription.
phenacaine Hcl 1.0% (Nacl eq=0.17)
Chlorobutanol 0.5% ( Nacl eq=0.18)
Boric acid qs (Nacl eq=0.52)
Purified H2O ad 30 ml.
Make isotonic solution.

 

[kt44]

plz help me in solving these calculations.
1- how many grams of boric acid should be used in compounding the following prescription.
phenacaine Hcl 1.0% (Nacl eq=0.17)
Chlorobutanol 0.5% ( Nacl eq=0.18)
Boric acid qs (Nacl eq=0.52)
Purified H2O ad 30 ml.
Make isotonic solution.

a pharmacist prepares one gallon of KCL solution by mixing 565 gram of KCL (valence 1) in an approppriate vehicle. how many milliequivalent of K are in 15ml of this solution.( molecular weight KCL 65.5)