Need help with acceleration question! (MCAT studying)

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Tobi222

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Hi, I'm currently doing a question from a passage on Uworld qbank and I need help understanding why my method doesn't work? I'm sure I'm missing something. The question (doesn't really apply to the passage) states:

"In one experimental trial, the projectile was uniformly accelerated from rest to a distance of 2 m in 0.1 s. What was the acceleration of the projectile?"
Answer: 400 m/s^2
My answer: 200 m/s^2.

Using the distance (2 m) and time (0.1 s) given, I got the velocity (20 m/s) and I used the equation of velocity divided by time to find the acceleration (20 m/s / 0.1 s), which is how I got 200 m/s^2 but it's wrong. The qbank got 400 m/s^2 by using the kinematic formula: d = v0t + 1/2at^2. Upon reading their calculations, I understand how they got 400 m/s^2 but I'm just wondering why the equation I used (a=v/t) can't work? Is it because it's only used for non-constant/non-uniform acceleration only? Or only used for average acceleration only?

Sorry for the dumb questions. I just wanted to clarify! Every time I think I understand something, I realize I don't lol

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I think the equation: d = [(Vi+ Vf) / 2] * t, might help you visualize things.

When you use d / t, you are actually calculating average velocity, meaning, the velocity that would need to be maintained for the entire time interval for you to reach that distance. With acceleration however, you start slower and end faster than the average velocity. The nice thing is, you can just multiply by 2 in this instance to get the max velocity: (Vf - Vi) / 2 = average velocity --> 2V = Vf - Vi

Does that help?
 
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