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Quantitatively, is normality just molarity*van't Hoff factor?
Not necessarily...
1 M sulfuric acid (H2SO4) is 2 N for acid-base reactions because each mole of sulfuric acid provides 2 moles of H+ ions. (where you're getting that conclusion from I suppose). So you could make that generalizations for strong acids in acid-base reactions, where they completely dissociate into their ions.
1 M sulfuric acid is 1 N for sulfate precipitation, since 1 mole of sulfuric acid provides 1 mole of sulfate ions.
Okay, so you are right, but only in solutions...
Normality = Molarity 👎 . Where n is the number of protons, hydroxide ions, electrons or monovalent ions (so PO43- doesn't apply) "produced" or "consumed" per molecule of the compound in any reaction. So I would say 2.25 N.
van't Hoff factor is related only to solutions. Definition by Kaplan is: van't Hoff facotr is "the moles of particles dissolved in a solution per mole of solute molecules". So that's why you can indeed say that Normality = molarity (i) for acid-base reactions for example, b/c they are conducted in aqueous solution.
At least that's how I understand. If I'm wrong...then I don't want to be right! Jk! correct me.😛
Oh, but did the below makes sense?
Normality = Molarity 👎 . Where n is the number of protons, hydroxide ions, electrons or monovalent ions (so PO43- doesn't apply) "produced" or "consumed" per molecule of the compound in any reaction.
Normality = N = Molarity of the species that matter.
1 M HCl = 1 N HCl
1 M H2SO4 = 2 N H2SO4
1 M H3PO4 = 3 N H3PO4
I think the convention to only count either the number of protons or the monovalent ions. So that's why the definition still applies
"n is the number of protons, hydroxide ions, electrons or monovalent ions (so PO43- doesn't apply) "produced"