Why are these not conformational isomers? They are actually enantiomers.

Just assign priorities and find the absolute conformation. The one on the left is S and the one on the right is R.
You can think of it this way, too- take either one of them and rotate is 180 degrees. Then it should be clear to you that they're mirror images.
because they are non-superimposable mirror images?
what is the "?" for? I usually use that in the context of "well duh", and your response seems rude. but maybe you had different intentions than i am interpreting.
if not, please have some respect.
That's the best way then. Just do whatever you're most comfortable with.hahaha--when people give me the definition of enantiomer (" are non-superimposable mirror images") , it's embarrassing unfortunately, i can't see that 😳
i think i'm just gonna have to resort to checking absolute confirmation, b/c it's difficult for me to see the answer.
I use it when I have a reasonable suggestion but I'm not 100% sure that I'm correct?
You have to reverse the direction on a Fisher Projection when the low priority group is coming out of the page (on one of the sides).Isn't the left one R and the right one S? OH highest priority then C2H2 second highest priority.
Isn't the left one R and the right one S? OH highest priority then C2H2 second highest priority.
hahaha--when people give me the definition of enantiomer (" are non-superimposable mirror images") , it's embarrassing unfortunately, i can't see that 😳
i think i'm just gonna have to resort to checking absolute confirmation, b/c it's difficult for me to see the answer.
In fischer projections, think "horizontal is horribly wrong". Meaning whenever hydrogen is horizontal (pointing out of the page), whatever configuration you get is wrong. So if you get R, it's actually S.
A trick to remember with these types of questions is that the switching of any two groups results in an enantiomer. In this case, the Me and Et are switched.