This is a 4 step reaction but I am confused about step 2.
2-chloro-butane reacts with (potassium-tert-butoxide/ tert-butanol) which reduces the alkyl halide and forms a double bond. I am confused as to where the double bond is placed because in the solutions the double bond is between C1 and C2 and I thought that the double bond would go between C2 and C3, as the more stable form. Does anyone know why 1-butene forms and not 2-butene?
2-chloro-butane reacts with (potassium-tert-butoxide/ tert-butanol) which reduces the alkyl halide and forms a double bond. I am confused as to where the double bond is placed because in the solutions the double bond is between C1 and C2 and I thought that the double bond would go between C2 and C3, as the more stable form. Does anyone know why 1-butene forms and not 2-butene?