OC Destroyer #119

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rah08e

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This is a 4 step reaction but I am confused about step 2.

2-chloro-butane reacts with (potassium-tert-butoxide/ tert-butanol) which reduces the alkyl halide and forms a double bond. I am confused as to where the double bond is placed because in the solutions the double bond is between C1 and C2 and I thought that the double bond would go between C2 and C3, as the more stable form. Does anyone know why 1-butene forms and not 2-butene?
 
This is a 4 step reaction but I am confused about step 2.

2-chloro-butane reacts with (potassium-tert-butoxide/ tert-butanol) which reduces the alkyl halide and forms a double bond. I am confused as to where the double bond is placed because in the solutions the double bond is between C1 and C2 and I thought that the double bond would go between C2 and C3, as the more stable form. Does anyone know why 1-butene forms and not 2-butene?



Good question; Remember one thing, a BULKY BASE such as pottassium butoxide, will ALWAYS direct the alkene into ANTI zaitsev and not the usual alkene. Anytime you see a bulky base thats tertiary or such will always form the opposite of what you are used to

Im not sure if you have watched chads videos, but he emphasizes this topic a great deal. I really recommend watching them if you still havent.
 
Good question; Remember one thing, a BULKY BASE such as pottassium butoxide, will ALWAYS direct the alkene into ANTI zaitsev and not the usual alkene. Anytime you see a bulky base thats tertiary or such will always form the opposite of what you are used to

Im not sure if you have watched chads videos, but he emphasizes this topic a great deal. I really recommend watching them if you still havent.

Where do I go to access chads videos?
 
I have chads videos but I have only gone over gen chem. Also, thanks for your reply. I actually asked a friend about this and he offered a similar explanation.
 
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