ochem question #30 in subject test 2

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A mixture of alkyl halides is subjected to elimination (E1) with one mole of aqueous acid and alcohol. If the reactant mixture initially contains one mole each of n-propyl chloride and isopropyl chloride, what can be predicted about the product mixture?

RX + R'X H + /H2O and CH3 CH2 OH-> products

A. A single alkene product is formed, and isopropyl chloride is present in excess.
B. A single alkene product is formed, and n-propyl chloride is present in excess.
C. Two distinct alkene products are formed, and n-propyl chloride is present in excess.
D. Two distinct alkene products are formed, and isopropyl chloride is present in excess.
E. No reaction occurs because both alkyl halides used are inert to elimination (E2).

I thought it would be A since E1 prefers to react with compounds with less steric hindrance. But kaplan says it is B. What do you think?
 
B for sure. When you form your carbocation with the isopropyl, it requires no rearrangement. And it's secondary. Single alkene forms for sure: 1-propene.
 
B for sure. When you form your carbocation with the isopropyl, it requires no rearrangement. And it's secondary. Single alkene forms for sure: 1-propene.

Thank you, I get it now. I was thinking E2 and how they don't form carbocations..
 
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