I have several problems from the Kaplan material.
However, I think that the solution of the Kaplan is wrong.
Could you guys check for it? 🙂
DAT Review Note p316 - problem 5.
I think the answer is C, but the solution says the answer is D. Why?
DAT Subject Test 3 (org. chem) - problem 6.
I think the answer is C becuase it's anti-addition. How can A and D are anti-addition. Aren't they syn?
DAT Subject Test 3 (org. chem) - problem 8.
The reactant is secondary halide and nucleophie (NaOH) is strong base. Only E2 can occur. However, the solution said that depending on the condition, both Sn 2 and E2 can occur. I don't understand why. the conditions (secondary halide and strong base) are already given.
DAT Subject Test 5 (org. chem) - problem 24
The problem gave tertiary halide and weak base. Both E1 and Sn1 can occur. E1 means doulbe bond formation, and Sn 1 means loss of optical activity. So the answer can be both D and E. However, the solution said the answer is only E.
However, I think that the solution of the Kaplan is wrong.
Could you guys check for it? 🙂
DAT Review Note p316 - problem 5.
I think the answer is C, but the solution says the answer is D. Why?
DAT Subject Test 3 (org. chem) - problem 6.
I think the answer is C becuase it's anti-addition. How can A and D are anti-addition. Aren't they syn?
DAT Subject Test 3 (org. chem) - problem 8.
The reactant is secondary halide and nucleophie (NaOH) is strong base. Only E2 can occur. However, the solution said that depending on the condition, both Sn 2 and E2 can occur. I don't understand why. the conditions (secondary halide and strong base) are already given.
DAT Subject Test 5 (org. chem) - problem 24
The problem gave tertiary halide and weak base. Both E1 and Sn1 can occur. E1 means doulbe bond formation, and Sn 1 means loss of optical activity. So the answer can be both D and E. However, the solution said the answer is only E.
