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RX + 2 Li → RLi + LiX
How are both Li's oxidized? The way I'm thinking of it is that R is + and X is -.
So the products would be R+Li- and Li+X- (therefore one Li oxidized and one reduced. What am I doing wrong?
How are both Li's oxidized? The way I'm thinking of it is that R is + and X is -.
So the products would be R+Li- and Li+X- (therefore one Li oxidized and one reduced. What am I doing wrong?