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At a particular T and total pressure of 1.5 atm, consider the dimerization of nitrogen dioxide after starting with a mix of 1.0 moles of NO2 and 3.5 moles of N2O4. If the equilibrium pressure of nitrogen tetraoxide is 1.0 atm, the EQ amount of NO2 is closest to ..?
Ptotal = 1.5 atm = P(NO2) + P(N2O4)
P(NO2) = 0.50 atm.
P(N2O4)= 1.0 atm
K = P(N2O4)/(P(NO2))^2 = 1/0.50^2 = 4
So now we have the equilibrium constant.
Q = [N2O4]/[NO2]^2 = 4 = 3.5 moles / (1.0 moles)^2 = 3.5 < 4 = K.
Q < K.
Product forming reaction favored.
4 = 3.5+x/(1-2x)^2.
Unfortunately, this doesn't give me the right answer. What's up?
Ptotal = 1.5 atm = P(NO2) + P(N2O4)
P(NO2) = 0.50 atm.
P(N2O4)= 1.0 atm
K = P(N2O4)/(P(NO2))^2 = 1/0.50^2 = 4
So now we have the equilibrium constant.
Q = [N2O4]/[NO2]^2 = 4 = 3.5 moles / (1.0 moles)^2 = 3.5 < 4 = K.
Q < K.
Product forming reaction favored.
4 = 3.5+x/(1-2x)^2.
Unfortunately, this doesn't give me the right answer. What's up?