Physics Equation help

[752779]

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Hey guys I'm horrible at math, can anyone help me by breaking down the algebra.
How does this

becomes this

Thanks

 

[BerkReviewTeach]

• It would be easier to make (y - yo) a ∆y.
• By setting it equal to 0, you are doing a specific problem. Is the question, "what is the speed at impact after dropping an object from a certain height?" or "what vertical launch speed is necessary to reach a given height?" and they didn't give you time?" If so, you could use Vf^2 - Vi^2 = 2gd.
• There is a very good chance you are doing too much math here.

 

[aldol16]

You should be able to do basic algebraic manipulations for the MCAT although this particular equation is likely low yield.

Ignore the zero on the right side. Just work with the left-hand equality. 1) Subtract y0 from both sides 2) Subtract (1/2)at^2 from both sides. Divide both sides by t. This gives you the first equality on the bottom. Then, you probably copy and pasted this from some specific problem where the displacement in the y direction is 0. Which gives you -(1/2)at^2/t, which reduces to -(1/2)at.