Possible mistake in Destroyer Gen Chem question

[Flirteve]

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Hey, hope the studies are going great. I'm working on G. chem and came across something odd: I understand we have to use the combined gas law and the calculation would lead to answer A. However, the units of R = L x atm / K x mol, and 1 atm = 760 torr, so wouldn't we have to convert the Torr pressure to atm pressure first and then calcluate, which gives us choice E. Does anybody agree with this. Please let me know, thanks a bunch in advance for your help and don't hesitate to hit me up if you need help with anything. Good luck with the studies and for all of those whose big day is coming up this week, & even after that.

Here's a link to further prove my point:

http://members.aol.com/profchm/comb_gas.html

lol sorry about that, I posted it the first time and I was logged out after a few minutes, ugh.

Question 143 Thanks again

 

[polf]

it would be a lot more helpful if you listed the question # so we can look at it for you

 

[Flirteve]

it would be a lot more helpful if you listed the question # so we can look at it for you

Question 143

 

[rollredroll]

i looked at this problem the other day. i think if the units are consistent then it doesnt matter what you use for P (atm, torr, mmHg)

 

[Flirteve]

i looked at this problem the other day. i think if the units are consistent then it doesnt matter what you use for P (atm, torr, mmHg)

This sounds about right. Thanks so much man. In fact, I think this is a similar situation to the M1Vl = M2V2, where you would can use ml if that's given, as opposed to having to convert to liters if you're just using the equation: M = mol / vol. I guess this makes sense. If anyone else agrees with this, please share the wealth 🙂 Thanks a lot again & good luck studying!

 

[rollredroll]

you're spot on with the m1v1=m2v2 comparison. it's ok to use ml as long as you are consistent. good luck!