I did it this way.
Think about how many slots you have, technically, 38, but since 0 and 00 have 3 times the possibility of everything else, you can just assume you have 3 of each but with equal probability as everything else. Then, you'd have 42 possible outcomes.
Possibility of red even number: 9/42
Possibility of red 23: 1/42 (since it's a specific case and is not even, thus different than first one)
Possibility of 00: 3/42
since you have or, add them all up: 13/42