Question #293 on Dat destroyer G-C section, please help!

[stc190]

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293. A irreversible reaction A+B->C, which of the following will not effect the rate of the reaction?
A) decreasing A
B) increasing B
C)adding a catalyst
D) removing C
E) increasing the temperature
I chooses A) decreasing A, because if you decrease reactant A, the reaction will shift to left but due to the reaction is irreversible, therefor it cannot shif to left. But the correct choice is D) removing C. My question is if you remove C will the reaction be faster? Because it will shift right, same as common ion effect. If the product is removed, the forward reaction will faster.

 

[hockey553]

So the answer is D because it states the reaction is one way, therefore you cannot use Le Chatliers principle. If the reaction was at equilibrium than removing C would shift the reaction to the right. Changing A,B, adding a catalyst, and increasing the temperature will affect the rate of the reaction. Increasing A or B will increase the rate, so will temp as molecules will collide more frequently. Lastly a catalyst will lower Ea.

 

[DAT Destroyer]

293. A irreversible reaction A+B->C, which of the following will not effect the rate of the reaction?
A) decreasing A
B) increasing B
C)adding a catalyst
D) removing C
E) increasing the temperature
I chooses A) decreasing A, because if you decrease reactant A, the reaction will shift to left but due to the reaction is irreversible, therefor it cannot shif to left. But the correct choice is D) removing C. My question is if you remove C will the reaction be faster? Because it will shift right, same as common ion effect. If the product is removed, the forward reaction will faster.

Think about this,,,,If A was to decrease.....you are decreasing a REACTANT.......bad move......will indeed slow you down !!! Don't confuse speed ...a KINETIC parameter with EQUILIBRIUM......a Thermodynamic parameter. Removal of C....will not change the speed.....The product is already made,,,,,,and the reaction in Irreversible .

Hope this Helps.

Dr. Romano

 

[stc190]

So the answer is D because it states the reaction is one way, therefore you cannot use Le Chatliers principle. If the reaction was at equilibrium than removing C would shift the reaction to the right. Changing A,B, adding a catalyst, and increasing the temperature will affect the rate of the reaction. Increasing A or B will increase the rate, so will temp as molecules will collide more frequently. Lastly a catalyst will lower Ea.

Thanks for replying, I didn't notice that it isn't a equilibrium😵

 

[stc190]

Think about this,,,,If A was to decrease.....you are decreasing a REACTANT.......bad move......will indeed slow you down !!! Don't confuse speed ...a KINETIC parameter with EQUILIBRIUM......a Thermodynamic parameter. Removal of C....will not change the speed.....The product is already made,,,,,,and the reaction in Irreversible .

Hope this Helps.

Dr. Romano

Thank you Dr. Romano. Now I know that one way reaction isn't a equilibrium due to there is not reverse rate.