question 78 of destroyer GC

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

marmar

Full Member
10+ Year Member
15+ Year Member
Joined
Jul 5, 2008
Messages
61
Reaction score
0
does anyone else think the question 78 of gc in destroyer eventhough simple seem to be wrong? I do not understand how d is not the answer. I mean logically you can not have 2 moles of sth alone and get sth else and a mole of original substance back. how?😕
 
I went through destroyer twice already and both times I got the question wrong and wrote choice D as my answer. But lets take out of the destroyer what we can. Yes in truth D seems like a good answer, but the Destroyer is coming usually to tell us something thats in the explained part.
This is it: the more reactants needed to come together for a reaction to take place the less likely the reaction is to occur.
 
As a fact it is nearly impossible for four different molecules to all colide at the same time with the required energy for a reaction. The chances of that happening are like 1 in a billion or less. Therefore that is not a possible reaction. All of the other reactions are possible. If you still have a question please post all of the answer choices so that i can explain why your answer is incorrect. I dont know exactly how the answer was written or what it said.
 
I'm curious since I put down D too 😛

a) X + Y ----> Z

b) 2X + Y ----> Z

c)2X + 2Y ----> W + Z

d) 2X ----> X + Y

e) 2X + Y ----> 2W + Z

If someone could explain the concepts of this problem that would be appreciated too since this isn't covered in the kaplan bluebook 😳
 
I'm curious since I put down D too 😛

a) X + Y ----> Z

b) 2X + Y ----> Z

c)2X + 2Y ----> W + Z

d) 2X ----> X + Y

e) 2X + Y ----> 2W + Z

If someone could explain the concepts of this problem that would be appreciated too since this isn't covered in the kaplan bluebook 😳

Basically in D what happened is a basic decomposition where X was partially degraded to Y and part of X didnt decompose and was left over and therefore appears in both the products and reactants. The main thing to understand is that C is impossible because there is no such thing as a tetra molecular-reaction.
 
Top