Question on Bootcamp GC #10, Q19

[DrHJ]

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Hi,
Q19 of BC GC#10 is asking about the plot of different order of a reaction.
For the zero order reaction, isn't it 2[A] vs Time linear? I was thinking when the plot of [A] vs. Time is linear then 2[A] vs. Time is also linear.

 

[Syxx]

Remember rate constants are determined experimentally by measuring the changes in concentrations of reactants/products over time. That's the beauty of these graphs, by plotting the concentration over time you can get the rate constant.

Here is what you are actually graphing for a 0th order reaction.

[A]t = -kt + [A]initial which is your line y = mx + b. You are asking what happens if you graph 2[A]t instead of [A]t for the same reaction in the same conditions ?
Yes, it would be linear but you would get a different k (rate constant) that wouldn't be the real rate constant of the reaction.

 

[DrHJ]

Remember rate constants are determined experimentally by measuring the changes in concentrations of reactants/products over time. That's the beauty of these graphs, by plotting the concentration over time you can get the rate constant.

Here is what you are actually graphing for a 0th order reaction.

[A]t = -kt + [A]initial which is your line y = mx + b. You are asking what happens if you graph 2[A]t instead of [A]t for the same reaction in the same conditions ?
Yes, it would be linear but you would get a different k (rate constant) that wouldn't be the real rate constant of the reaction.

Thank you very much for your detailed explanation. But here in this question is just asking which graph is linear.