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- Aug 2, 2010
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This question was on the practice DAT for ADA, could someone please explain?
During a titration it was determined that
30.00 mL of a 0.100 M Ce4+ solution was
required to react completely with 20.00
mL of a 0.150 M Fe2+ solution. Which
reaction occurred?
A. Ce4+ + 3Fe2+ + H2O 3Fe3+
+ CeO- + 2H+
B. 2Ce4+ + Fe2+ Fe4+ + 2Ce3+
C. Ce4+ + Fe2+ Fe3+ + Ce3+
D. Ce4+ + 2Fe2+ 2Fe3+ + Ce2+
E. Ce4+ + 2Fe2+ 2Fe4+ + Cs2+ 2e-
During a titration it was determined that
30.00 mL of a 0.100 M Ce4+ solution was
required to react completely with 20.00
mL of a 0.150 M Fe2+ solution. Which
reaction occurred?
A. Ce4+ + 3Fe2+ + H2O 3Fe3+
+ CeO- + 2H+
B. 2Ce4+ + Fe2+ Fe4+ + 2Ce3+
C. Ce4+ + Fe2+ Fe3+ + Ce3+
D. Ce4+ + 2Fe2+ 2Fe3+ + Ce2+
E. Ce4+ + 2Fe2+ 2Fe4+ + Cs2+ 2e-