I believe the ethyl is the 3rd priority.
For the top group, it is a carbon attached to only 1 carbon.
For the right group, it is carbon attached to 2 carbons(One of them being from the methyl group. The second is part of the ring).
The carbon with 2 carbons attached to it will get a higher priority than the other with only 1 carbon attached.
Clockwise is R. It goes counterclockwise, so it is S.