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how many moles of AGIO3 (Ksp= 3.1x10^-8) will dissolve in one liter of 10^-5 M solution of NAIO3?
I know that
AGIO3 -> AG ion + IO3 ion
and since ksp = 3.1 x 10 ^-8 ,
3.1 x 10^-8 = x^2
x = sqr root of 3.1 x 10^-8
and we have 10^-5 M solution of NAIO3
NAIO3 -> NA ion + IO3 ion
(10^05M) (10^-5M) (10^-5M)
and since we added more IO3 , common ion effect will take place and this rxn will shift left..
but i don't know why answer is
(sqr root of 3.1x10^-8) - (10^-5M)
shouldn't it be
(10^-5M) - (sqr root of 3.1x10^-8) ?
thanx
I know that
AGIO3 -> AG ion + IO3 ion
and since ksp = 3.1 x 10 ^-8 ,
3.1 x 10^-8 = x^2
x = sqr root of 3.1 x 10^-8
and we have 10^-5 M solution of NAIO3
NAIO3 -> NA ion + IO3 ion
(10^05M) (10^-5M) (10^-5M)
and since we added more IO3 , common ion effect will take place and this rxn will shift left..
but i don't know why answer is
(sqr root of 3.1x10^-8) - (10^-5M)
shouldn't it be
(10^-5M) - (sqr root of 3.1x10^-8) ?
thanx