Solving for x^2 w/ an exponent

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Indie

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Hey guys, Im trying to do a gchem problem where I have to solve for Kb in a 2M solution and i've gotten as far in the problem as:
Kb= 6x10^-4 = x^2/2M

There are 2 products formed so it is [x] [x] = x^2


Now to eliminate the denominator it would be 6x10^-4 *(2) = x^2
= 12x10^-4 ---> 1.2x10^-3 = X^2

Basically in a nutshell, im asking how do you solve for the sqrt of 1.2x10^-3 without a calculator???

Any advice??
Thanks...
 
tinman831 said:
Assuming that is the answer, you would not have to simplify the answer any further on the DAT.



1.2x10^-3 = X^2

Thats not the answer... I need to solve for X... right now the above is Xsqrd

If you Square root 1.2x10^-3

you get 3.5x10^-2 but I can't do that without a calculator... I keep getting stuck at this step..

then I would find 2 - log 3.5 etc... etc... etc....
 
Indie said:
1.2x10^-3 = X^2

Thats not the answer... I need to solve for X... right now the above is Xsqrd

If you Square root 1.2x10^-3

you get 3.5x10^-2 but I can't do that without a calculator... I keep getting stuck at this step..

then I would find 2 - log 3.5 etc... etc... etc....

The DAT will never give you a problem with such a complicated solution. A solution you might end up with, would be reducable without a calculator (like sqaure root of 4x10^4 = 2x10^2).
 
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